Physics - Modern Physics Question with Solution | TestHub

Nuclear radii $R=\left(R_0\right)A^{1/3}$ where, $A$ is the mass number. $\frac{R_{\mathrm{Te}}}{R_{\mathrm{Al}}}={\left(\frac{A_{\mathrm{Te}}}{A_{\mathrm{Al}}}\right)}^{1/3}={\left(\frac{125}{27}\right)}^{1/3}=\left(\frac{5}{3}\right)$ or, $R_{\mathrm{Te}}=\frac{5}{3}\times R_{\mathrm{Al}}=\frac{5}{3}\times 3.6=6\mathrm{fm}$. (Given $R_{\mathrm{Al}}=3.6\mathrm{fm}$)