A hydrogen atom in its ground state absorbs a photon of energy 10.2 eV and gets excited. The change in angular momentum of the electrons in this process is (in kgm 2 / s ) nearly:

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The energy absorbed corresponds to the transition from $n = 1$ to $n = 2$ .

The change in angular momentum is

$Δ L = L_{2} - L_{1} = 2ℏ - 1ℏ = ℏ = \frac{h}{2 π} \approx 1.05 \times 1 0^{- 34} kgm^{2} / s$ .

Thus, the answer is approximately $1 \times 1 0^{- 34} kgm^{2} / s$ .

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