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PhysicsModern PhysicsPhotoelectric effectMedium2 minPYQ_2006

PhysicsMediumstatement

The threshold frequency for a metallic surface corresponds to an energy of $6.2 eV$ , and the stopping potential for a radiation incident on this surface $5 V$ . The incident radiation lies in

Options:

Answer:

Solution:

$λ = \frac{1242 e V nm}{11.2} \approx 1100 \overset{˚}{A}$ Ultraviolet region

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2006

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