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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectEasy2 minPYQ_2020

PhysicsEasysingle choice

The threshold frequency for a metallic surface corresponds to an energy of $6.2 e V$ and the stopping potential for a radiation incident on this surface is $5 V$ . The incident radiation lies in

Options:

Answer:

Solution:

We know that

$E = w_{0} + {KE}_{\max}$

$\frac{h c}{λ} = 5 eV + 6.2 eV = 11. 2 e V$

$λ = \frac{12400}{11 \cdot 2} Å$

$λ = 1107 Å$

This lies in Ultra Violet light Region.

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect

⏱ 2mℹ️ Source: PYQ_2020

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