A wire of uniform cross-section is hanging vertically and due to its own weight its length changes. There is a point C on the wire such that change in length AC is equal to the change in length BC . Points $A, B & C$ are shown in figure. Find $\frac{AC}{BC}$ .

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TestHub · Accepted Answer

For a hanging wire, extension of a segment is found by integrating local tension. Equating the two segment extensions gives AC/BC=√2-1.

Physics - Mechanical Properties of Solids Question with Solution | TestHub

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