A rod of mass m, uniform cross sectional area A and length L is accelerated by applying force F as shown in figure on a smooth surface. If Young's modulus of elasticity of the material of rod is Y. (Consider x as measured from the right end)

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At section x from the free/right end, tension is Fx/L.

Integrating T²/(2AY) gives U=F²L/(6AY); among the printed claims only the linear-tension form and corresponding stored-energy claim are marked by source convention.

Physics - Mechanical Properties of Solids Question with Solution | TestHub

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