Physics - Mechanical Properties of Solids Question with Solution | TestHub

PhysicsMechanical Properties of SolidsElasticityMedium3 minCT48

PhysicsMediumsingle choice

Passage / Comprehension

a ring of mass m and radius R rolls with constant speed v on a horizontal surface. Its material has Young modulus y and the wire cross-sectional area is A.

Change in radius of the ring due the its motion is :-

Options:

Answer:

Solution:

For a thin ring, mass per unit length is $l amb d a = f r a c m 2 p i R$ .

Balancing centripetal force for a small element gives $T = l amb d a v^{2} = f r a c m v^{2} 2 p i R$ .

Stress is $s i g ma = f r a c T A$ and strain is $f r a c De lt a R R = f r a c s i g ma y$ .

Hence, $De lt a R = f r a c m v^{2} 2 p i A y$ , so option B is correct.

Stream:JEESubject:PhysicsTopic:Mechanical Properties of SolidsSubtopic:Elasticity

⏱ 3mℹ️ Source: CT48

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