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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium2 minQB

PhysicsMediumsingle choice

A particle of charge $q$ , mass $m$ and kinetic energy E enters in magnetic field perpendicular to its velocity and undergoes a circular arc of radius( r). Which of the following curves represents the variation of $r$ with $E$ ?

Options:

Answer:

Solution:

$\frac{mv ^{2}}{r} = qvB$
$mv = qBr$
$E = \frac{1}{2} mv^{2}$
$E = \frac{1}{2} m (\frac{q ^{2} B ^{2} r ^{2}}{m ^{2}}) = \frac{q ^{2} B ^{2} r ^{2}}{2 m}$
$E = (\frac{q ^{2} B ^{2}}{2 m}) r^{2}$
$r^{2} \propto E$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: QB

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