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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB

PhysicsMediumsingle choice

A wire carrying current $I$ is bent in the shape $ABCDEFA$ as shown, where rectangle $ABCDA$ and $ADEFA$ are perpendicular to each other. If the sides of the rectangles are of lengths $a$ and $b$ , then the magnitude and direction of magnetic moment of the loop $ABCDEFA$ is :

Options:

Answer:

Solution:

Loop ABCD

${\vec{M}}_{1} = (abI) (\hat{k})$
For Loop DEFA ${\vec{M}}_{2} = (abI) (\hat{j})$
$\vec{M} = {\vec{M}}_{1} + {\vec{M}}_{2}; \vec{M} = (a b I) (\hat{j} + \hat{k})$
$\sqrt{2} a b I$ along $(\frac{\hat{j}}{\sqrt{2}} + \frac{\hat{k}}{\sqrt{2}})$ .

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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