Figure shows a current carrying square loop ABCD of edge length is ' $a$ ' lying in a plane. If the resistance of the $A BC$ part is $r$ and that of $A D C$ part is 2 r , then the magnitude of the resultant magnetic field at centre of the square loop is

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B = B AB ​ + B BC ​ + B CD ​ + B DA ​ B = B = B = ​ [ 4 π ( a /2 ) − μ 0 ​ ( 2 I /3 ) ​ 2 ​ − 4 π ( a /2 ) μ 0 ​ ( 2 I /3 ) ​ 2 ​ + 4 π ( a /2 ) μ 0 ​ ( I /3 ) ​ 2 ​ + 4 π ( a /2 ) μ 0 ​ ( I /3 ) ​ 2 ​ ] k ^ [ 3 π a − 2 2 ​ μ 0 ​ I ​ + 3 π a 2 ​ μ 0 ​ I ​ ] k ^ 3 π a − 2 ​ μ 0 ​ I ​ k ^ ​

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