A singly ionized magnesium atom A = 24 ion is accelerated to kinetic energy 5 keV , and is projected perpendicularly into a magnetic field B of the magnitude 0 . 5 T . The radius of path formed will b

Question

A singly ionized magnesium atom A = 24 ion is accelerated to kinetic energy 5 keV , and is projected perpendicularly into a magnetic field B of the magnitude 0 . 5 T . The radius of path formed will be _____ cm .

TestHub · Accepted Answer

The radius of circle formed by a charged particle in a magnetic field perpendicular to the velocity is given by,

$R = \frac{m V}{q B} \Rightarrow R = \frac{\sqrt{2 m K}}{q B} = \frac{\sqrt{2 \times 24 \times 1.6 \times 10^{- 27} \times 5000 \times 1.6 \times 10^{- 19}}}{1.6 \times 10^{- 19} \times 0.5} = 979 \times 10^{- 4} m ≃ 10 cm$

Physics - Magnetism Question with Solution | TestHub

Doubts & Discussion