Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium2 minPYQ_2020

PhysicsMediumsingle choice

A charged particle enters a uniform magnetic field with a velocity vector at an angle of $45 °$ with the magnetic field. The pitch of the helical path followed by the particle is $p$ . The radius of the helix will be -

Options:

Answer:

Solution:

Pitch of helical path is,

$p = (v \cos θ) \times \frac{2 π m}{q B} = \frac{2 π m v \cos 45 °}{q B}$

$= \frac{2 π m v}{\sqrt{2} q B}$

Also radius of helix is,

$r = \frac{m v \sin θ}{q B} = \frac{m v}{\sqrt{2} q B}$

$∴ \frac{r}{p} = \frac{m v}{\sqrt{2} q B} \times \frac{\sqrt{2} q B}{2 π m v} = \frac{1}{2 π}$

or $r = \frac{p}{2 π}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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