Physics - Magnetism Question with Solution | TestHub

Due to current in BA is $\overrightarrow{\mathrm{B}}=-\frac{{\mu }_0\mathrm{i}}{\sqrt{6}\pi \mathrm{a}}(\hat{\mathrm{i}}+\hat{\mathrm{j}})$

Due to current in BA is $\overrightarrow{\mathrm{B}}=\frac{{\mu }_0\mathrm{i}}{4\sqrt{6}\pi \mathrm{a}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}+\sqrt{3}\hat{\mathrm{k}})$

Due to current in BA is $\overrightarrow{\mathrm{B}}=-\frac{{\mu }_0\mathrm{i}}{2\sqrt{3}\pi \mathrm{a}}(\hat{\mathrm{i}}+\hat{\mathrm{j}})$

Due to current in $BA$ is $\vec{B}=\frac{{\mu }_{0}i}{4\sqrt{6}\pi \mathrm{a}}(\hat{i}+\hat{j}+\sqrt{2}\hat{k})$