If the magnetic moment and the pole strength of a bar magnet are 3.6 × 10 - 3 A m 2 and 120 × 10 - 3 A m , then its magnetic length is

For a bar magnet, the magnetic moment is M = p o l e s t r e n g t h × m a g n e t i c l e n g t h So the magnetic length will be l mag = M m ⇒ l mag = 3.6 × 10 - 3 120 × 10 - 3 = 3 × 10 - 2 m = 3 c m

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PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

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If the magnetic moment and the pole strength of a bar magnet are $3.6 \times 10^{- 3} A m^{2}$ and $120 \times 10^{- 3} A m$ , then its magnetic length is

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Solution:

For a bar magnet, the magnetic moment is

$M = p o l e s t r e n g t h \times m a g n e t i c l e n g t h$

So the magnetic length will be

$l_{mag} = \frac{M}{m}$

$\Rightarrow l_{mag} = \frac{3.6 \times 10^{- 3}}{120 \times 10^{- 3}} = 3 \times 10^{- 2} m = 3 c m$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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