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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minQB

PhysicsEasysingle choice

A proton and an alpha particle of the same velocity enter in a uniform magnetic field which is acting perpendicular to their direction of motion. The ratio of the radii of the circular paths described by the alpha particle and proton is

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Solution:

Radius of circular path of charged particle $(q)$ of mass $(m)$ moving with velocity $(v)$ in magnetic field $(B)$ is given by $r = \frac{m v}{q B}$

$\frac{r_{α}}{r_{p}} = \frac{\frac{(4 m) v}{(2 e) B}}{\frac{m v}{e B}} = 2 : 1$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: QB

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