A magnetic needle lying parallel to a magnetic field requires $W$ units of work to turn it through $6 0^{\circ}$ . The torque needed to maintain the needle in this position will be
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Answer:
A
Solution:
$τ = (H) tan 6 0^{\circ} = W \cdot 3$

Question

A magnetic needle lying parallel to a magnetic field requires W units of work to turn it through 6 0 ∘ . The torque needed to maintain the needle in this position will be

TestHub · Accepted Answer

τ = ( H ) tan 6 0 ∘ = W ⋅ 3 ​

Physics - Magnetism Question with Solution | TestHub

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