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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB

PhysicsMediumsingle choice

A charge particle moves from point M( $- a$ , 0) to N( $a$ , 0) along X-axis with constant velocity. The magnetic field at point P(0, $a$ ) will :

Options:

Answer:

Solution:

For a particle at coordinate x, the field magnitude at P is:

$B = \frac{μ _{0} ∣ q ∣ v a}{4 π ( x ^{2} + a ^{2} ) ^{3/2}}$

As x goes from -a to 0, B increases; from 0 to a, B decreases. Answer C.

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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