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PhysicsMagnetismMagnetic torque & energyHard2 minPYQ_2023
PhysicsHardsingle choice

A current carrying rectangular loop PQRS is made of uniform wire. The length PR=QS=5 cm and PQ=RS=100 cm. If ammeter current reading changes from I to 2I, the ratio of magnetic forces per unit length on the wire PQ due to wire RS in the two cases respectively fPQI:fPQ2I is:

Question diagram: A current carrying rectangular loop P Q R S is made of unifo

Options:

Answer:
B
Solution:

Force acting per unit length between two parallel wires is given by, f=μ0I1I22πd.

Clearly, fI1I2

Therefore, fPQI:fPQ2I=I×I2I×2I=1:4

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy
2mℹ️ Source: PYQ_2023

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