A charge particle is moving in a uniform magnetic field ( 2 i ^ + 3 j ^ ) T . If it has an acceleration of ( α i ^ − 4 j ^ ) m / s 2 , then the value of α will be :

Given that uniform magnetic field, B = ( 2 i ^ + 3 j ^ ) T Acceleration a = ( α i ^ − 4 j ^ ) m / s 2 We know that F = q ( v × B ) ⇒ m a = q ( v × B ) Here, a ⊥ B , so, a ⋅ B = 0 ( α i ^ − 4 j ^ ) ( 2 i ^ + 3 j ^ ) = 0 ⇒ 2 α − 12 = 0 ⇒ α = 6

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PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2023

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A charge particle is moving in a uniform magnetic field $(2 \hat{i} + 3 \hat{j}) T$ . If it has an acceleration of $(α \hat{i} - 4 \hat{j}) m / s^{2}$ , then the value of $α$ will be :

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Given that uniform magnetic field, $B = (2 \hat{i} + 3 \hat{j}) T$
Acceleration $a = (α \hat{i} - 4 \hat{j}) m / s^{2}$ We know that
$F = q (v \times B) \Rightarrow m a = q (v \times B)$
Here, $a ⊥ B$ , so, $a \cdot B = 0$
$(α \hat{i} - 4 \hat{j}) (2 \hat{i} + 3 \hat{j}) = 0 \Rightarrow 2 α - 12 = 0 \Rightarrow α = 6$

Stream:BITSATSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2023

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