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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minQB

PhysicsMediumnumerical

A uniform conducting wire of length is $24 a,$ and resistance $R$ is wound up as a current carrying coil in the shape of an equilateral triangle of side $a$ and then in the form of a square of side $a$ . The coil is connected to a voltage source $V_{0} .$ The ratio of magnetic moment of the coils in case of equilateral triangle to that for square is $1 : \sqrt{y}$ where $y$ is ____________.

Answer:

3.00

Solution:

$4 a n_{1} = 24 a$

thus $n_{1} = 6$ turns

$3 {an}_{2} = 24 a \Rightarrow n_{2} = 8$ turns

$\frac{M_{1}}{M_{2}} = \frac{n_{1} i A_{1}}{n_{2} i A_{2}} = \frac{6 \times a^{2}}{8 \times a^{2} \times \frac{\sqrt{3}}{4}} = \frac{\sqrt{3}}{1}$

$\frac{M_{2}}{M_{1}} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{y}}$

$y = 3$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: QB

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