A charge particle moving in magnetic field B , has the components of velocity along B as well as perpendicular to B . The path of the charge particle will be

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The formula to calculate the radius of the path followed by the charged particle under an external magnetic field can be written as
$r = \frac{m v}{B q} . . . (1)$
The perpendicular component of velocity results in circular motion, while the parallel component results in linear motion. Hence, the path of the charged particle is helical in nature, the axis of which lies along the direction of the magnetic field.

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