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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic torque & energyMedium2 minPYQ_2016

PhysicsMediumsingle choice

A square loop $ABCD$ carrying a current $i$ , is placed near and coplanar with a long straight conductor $XY$ carrying a current $I$ , the net force on the loop will be:

NEET 2016 (Phase 1)

Options:

Answer:

Solution:

$F_{1} = \frac{μ_{0} I i L}{2 π \frac{L}{2}} = \frac{μ_{0} I i}{π}$

$F_{2} = \frac{μ_{0} I i L}{2 π \frac{3 L}{2}} = \frac{μ_{0} I i}{3 π}$

$∴ F_{n e t} = F_{1} - F_{2}$

$F_{n e t} = \frac{2}{3} \frac{μ_{0} I i}{π}$

Stream:NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy

⏱ 2mℹ️ Source: PYQ_2016

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