Physics - Magnetism Question with Solution | TestHub

Given: $\mathrm{n}=100$ turns $/\mathrm{m}$ $\mathrm{I}=5\mathrm{A}$ $\begin{array}{rl}\mathrm{B}& =\frac{{\mu }_0\mathrm{nI}}{2}\left(\sin {\varphi }_1+\sin {\varphi }_2\right)\\ \mathrm{B}& =\frac{{\mu }_0\times 100\times 5}{2}\left(\sin 45^{\circ }+\sin 45^{\circ }\right)\\ & =\frac{{\mu }_0\times 500}{2}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)\\ & =\frac{{\mu }_0\times 500}{2}\times \frac{2}{\sqrt{2}}={\mu }_{0}250\sqrt{2}\\ & =250\sqrt{2}{\mu }_0\end{array}$