A single turn current loop in the shape of a right angle triangle with side 5 cm , 12 cm , 13 cm is carrying a current of 2 A . The loop is in a uniform magnetic field of magnitude 0.75 T whose direct

Question

A single turn current loop in the shape of a right angle triangle with side 5 cm , 12 cm , 13 cm is carrying a current of 2 A . The loop is in a uniform magnetic field of magnitude 0.75 T whose direction is parallel to the current in the 13 cm side of the loop. The magnitude of the magnetic force on the 5 cm side will be 130 x ​ N . The value of ' x ' is

TestHub · Accepted Answer

The net magnetic field is acting in the direction of GF as shown in figures: Resolving $B$ into its components, amongst the components, only $B sin θ$ exerts force on side EF of current carrying loop. $∴ F_{EF} = I \times d (EF) \times B sin θ$ From figure $(a), sin θ = \frac{12}{13}$ $∴ ∴ ∴ F_{EF} = 2 \times 0.05 \times 0.75 \times \frac{12}{13}, F_{EF} = \frac{9}{130} N x = 9$

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