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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawHard2 minPYQ_2023

PhysicsHardsingle choice

A circular coil of radius ' $r$ ' and number of turns ' $n$ ' carries a current ' $I$ '. The magnetic fields at a small distance ' $h$ ' along the axis of the coil $(B_{a})$ and at the centre of the coil $(B_{c})$ are measured. The ralation between $B_{c}$ and $B_{a}$ is

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Solution:

Magnetic field along the axis of the coil is: $B_{a} = \frac{μ _{0}}{4 π} [\frac{2 π nIr r ^{2}}{( r ^{2} + h ^{2} ) ^{\frac{3}{2}}}]$ Magnetic field at the centre of the coil is: $B_{C} \frac{B _{C}}{B _{a}} ∴ B_{C} = \frac{μ _{0}}{4 π} (\frac{2 π nI}{r}) = \frac{( r ^{2} + h ^{2} ) ^{\frac{3}{2}}}{r ^{3}} = B_{a} [1 + \frac{h ^{2}}{r ^{2}}]^{\frac{3}{2}}$

Stream:MHT_CETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2023

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