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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic torque & energyEasy2 minPYQ_2011

PhysicsEasysingle choice

A particle carrying a charge to 100 times the charge on an electron is rotating per second in a circular path of radius $0.8 m$ . The value of the magnetic field produced at the centre will be $(μ_{0} =$ permeabil ity for vacuum $)$

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Answer:

Solution:

Current, i $= \frac{q}{t} = 100 \times e$ $Magnetic field, B_{centre} = \frac{μ _{0}}{4 π} \cdot \frac{2 πi}{r} = \frac{μ _{0}}{4 π} \cdot \frac{2 π \times 100 e}{r} \frac{μ _{0} \times 200 \times 1.6 \times 1 0 ^{- 19}}{4 \times 0.8} = 1 0^{- 17} μ_{0}$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy

⏱ 2mℹ️ Source: PYQ_2011

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