Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawHard2 minPYQ_2022

PhysicsHardsingle choice

The magnetic field at the centre of a circular coil of radius $r$ , due to current I flowing through it, is $B$ . The magnetic field at a point along the axis at a distance $\frac{r}{2}$ from the centre is :

Options:

Answer:

Solution:

Magnetic field at the centre of the circle is, $B = \frac{μ_{0} i}{2 R}$

Magnetic field at the point on the axis is,

$B_{2} = \frac{μ_{0} i R^{2}}{2 {(R^{2} + x^{2})}^{\frac{3}{2}}} \Rightarrow B_{2} = \frac{μ_{0} i R^{2}}{2 {(R^{2} + {(\frac{R}{2})}^{2})}^{\frac{3}{2}}} \Rightarrow B_{2} = \frac{μ_{0} i}{2 {(\frac{5}{4})}^{\frac{3}{2}} R} = {(\frac{2}{\sqrt{5}})}^{3} B$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2022

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