Physics - Magnetism Question with Solution | TestHub

The magnetic field at a point $P$ due to a current carrying straight wire, such that the ends of the wires, makes angle $\alpha$ and $\beta$ (see figure) is given by $B=\frac{{\mu }_{0}I}{4\pi d}(\sin \alpha -\sin \beta )$ where, $d$ is the distance between the point $P$ and wire.In the given problem, $\alpha ={\theta }_1$ and $\beta ={\theta }_2$ $\therefore B=\frac{{\mu }_{0}I}{4\pi d}\left(\sin {\theta }_1-\sin {\theta }_2\right)$