A particle moving with velocity v → = i ^ + 3 j ^ produces an electric field E → = 2 k ^ at some point. It will produce a magnetic field at that point, which is equal to

B → = μ 0 4 π q v → × r → r 3 ⇒ E → = 1 4 π ε 0 q r → r 3 B → = μ 0 ε 0 v → × E → = v → × E → c 2 B → = 6 i ^ - 2 j ^ c 2

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PhysicsMagnetismMotion analysis in electric & magnetic fieldMedium2 minPYQ_2020

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A particle moving with velocity $\vec{v} = \hat{i} + 3 \hat{j}$ produces an electric field $\vec{E} = 2 \hat{k}$ at some point. It will produce a magnetic field at that point, which is equal to

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Answer:

Solution:

$\vec{B} = \frac{μ_{0}}{4 π} \frac{q \vec{v} \times \vec{r}}{r^{3}} \Rightarrow \vec{E} = \frac{1}{4 π ε_{0}} \frac{q \vec{r}}{r^{3}}$

$\vec{B} = μ_{0} ε_{0} (\vec{v} \times \vec{E}) = \frac{\vec{v} \times \vec{E}}{c^{2}}$

$\vec{B} =$ $\frac{6 \hat{i} - 2 \hat{j}}{c^{2}}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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