A current I flows in a circular arc of wire which subtends an angle 3 π 2 radians at its centre, whose radius is R . The magnetic induction B at the centre is

For a loop, magnetic induction at centre B = μ 0 4 π × 2 π i r When loop subtends angle θ at centre, then B = μ 0 4 π × θ i r (Here angle is θ instead of 2 π ) In the given problem, θ = 3 π 2 and r = R ∴ B = μ 0 4 π × 3 π 2 × i R = 3 μ 0 i 8 R

Start Free Mock LoginAlready registered? Login here

Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A current $I$ flows in a circular arc of wire which subtends an angle $\frac{3 π}{2}$ radians at its centre, whose radius is $R$ . The magnetic induction $B$ at the centre is

Options:

Answer:

Solution:

For a loop, magnetic induction at centre

$B = \frac{μ_{0}}{4 π} \times \frac{2 π i}{r}$

When loop subtends angle $θ$ at centre, then

$B = \frac{μ_{0}}{4 π} \times \frac{θ i}{r}$ (Here angle is $θ$ instead of $2 π$ )

In the given problem, $θ = 3 \frac{π}{2}$ and $r = R$

$∴$ $B = \frac{μ_{0}}{4 π} \times \frac{3 π}{2} \times \frac{i}{R} = \frac{3 μ_{0} i}{8 R}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...