The figure shows two regions of uniform magnetic fields of strengths B and 2 B . A charged particle of mass m and charge q enters the region of the magnetic field with a velocity v = q B w m , where w is the width of each region of the magnetic field. The time taken by the particle to come out of the region of the magnetic field is

Time = π m 2 qB + π m 2 qB = π m qB

Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldHard2 minPYQ_2020

PhysicsHardsingle choice

The figure shows two regions of uniform magnetic fields of strengths $B$ and $2 B$ . A charged particle of mass $m$ and charge $q$ enters the region of the magnetic field with a velocity $v = \frac{q B w}{m}$ , where $w$ is the width of each region of the magnetic field. The time taken by the particle to come out of the region of the magnetic field is

Options:

Answer:

Solution:

$Time = \frac{π m}{2 qB} + \frac{π m}{2 qB} = \frac{π m}{qB}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...