Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismProperties of magnetEasy2 minPYQ_2020

PhysicsEasysingle choice

At a place the true value of angle of dip is $60 °$ . If dip circle is rotated by $ϕ °$ from magnetic meridian, the angle of dip is found to be $\tan^{- 1} (2)$ . Then the value of $ϕ$ is

Options:

Answer:

Solution:

${\tan δ}^{'} = \frac{\tan δ}{\cos x^{o}}$

$\tan (\tan^{- 1} (2)) = \frac{\tan 60^{o}}{\cos x^{o}}$

Or, $\cos x ° = \frac{\sqrt{3}}{2}$

$∴ x = 30 °$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Properties of magnet

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...