A positive charge particle having charge q and mass m has velocity v → = v i ^ + k ^ 2 in the magnetic field B at the origin. Its speed as the function of y is :

Along y v y 2 = 2 × qE m × y Net speed = v 2 + v y 2

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

A positive charge particle having charge q and mass m has velocity $\vec{v} = v (\frac{\hat{i} + \hat{k}}{\sqrt{2}})$ in the magnetic field B at the origin. Its speed as the function of y is :

Options:

Answer:

Solution:

Along y $v_{y}^{2} = 2 \times \frac{qE}{m} \times y$

Net speed $= \sqrt{v^{2} + v_{y}^{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2020

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