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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

In a cyclotron, if a deuteron can gain an energy of $40 M e V$ , then a proton can gain an energy of

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Answer:

Solution:

Radius of the path

$R = \frac{\sqrt{2 m K}}{q B}$

$∵ R_{d} = R_{p}$

$∴ \frac{\sqrt{2 m_{d} K_{d}}}{q_{d} B} = \frac{\sqrt{2 m_{p} K_{p}}}{q_{p} B}$

or $\frac{\sqrt{2 (2 m_{p}) K_{d}}}{e B} = \frac{\sqrt{2 m_{p} K_{p}}}{e B}$

$∴$ $K_{p} = 2 K_{d} = 2 \times 40 MeV = 80 M e V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Force

⏱ 2mℹ️ Source: PYQ_2020

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