Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

In the diagram shown, $I_{1}$ , $I_{2}$ are the magnitudes of current in the square loop and infinite long straight conductor respectively. If the net magnetic field at the centre of the loop is zero, then the relation between $I_{1}$ and $I_{2}$ is

Options:

Answer:

Solution:

$\vec{B} = {\vec{B}}_{1} + {\vec{B}}_{2}$

$B_{1} = \frac{μ_{0} I_{2}}{2 π (\frac{3 a}{2})}$

$B_{2} = \frac{4 μ_{0} I_{1} \sqrt{2}}{4 π (\frac{a}{2})}$

$\frac{μ_{0} I_{2}}{3 π a} = \frac{2 μ_{0} I_{1} \sqrt{2}}{π a}$

$I_{2} = 6 I_{1} \sqrt{2}$

Subject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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