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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A long solenoid of $50 cm$ length having $100$ turns carries a current of $2.5 A$ . The magnetic field at the centre of the solenoid is:
$(μ_{0} = 4 π \times 10^{- 7} T m A^{- 1})$ NEET 2020 (Phase 1)

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Answer:

Solution:

The magnetic field at the centre of the solenoid is given by, $B = μ_{0} n i$

Where $n$ is the number of turns per unit length
$\Rightarrow B = 4 π \times 10^{- 7} \times \frac{100}{(0.5)} \times 2.5$
$\Rightarrow B = 6.28 \times 10^{- 4} T$

Stream:NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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