A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass m and radius r and it is in a uniform ve

Question

A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass $m$ and radius $r$ and it is in a uniform vertical magnetic field $B_{0}$ , as shown in the figure. Initially, it hangs vertically downwards, because of acceleration due to gravity $g$ , on two conducting supports at $P$ and $Q$ . When a current $I$ is passed through the loop, the loop turns about the line $PQ$ by an angle $θ$ given by

TestHub · Accepted Answer

​ Let loop makes angle θ with vertical. in equilibrium τ net ​ = 0 τ 0 ​ = MB sin ( 90 − θ ) − mg . r sin θ = 0 I. π r 2 ⋅ B 0 ​ cos θ = mg r.sin θ tan θ = mg π rIB 0 ​ ​ ​

Physics - Magnetism Question with Solution | TestHub

Options:

Doubts & Discussion