A magnet of moment 4 A m 2 is kept suspended in a magnetic field of induction 5 × 10 - 5 T . The work done in rotating it through 180 0 is

W = − M . B ( cos θ f − cos θ i ) = ( − ) 4 × 5 × 10 − 5 ( cos 180 − cos 0 ) = − 20 × 10 − 5 ( − 1 − 1 ) = 4 × 10 − 4 J

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismProperties of magnetEasy2 minPYQ_2020

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A magnet of moment $4 A m^{2}$ is kept suspended in a magnetic field of induction $5 \times 10^{- 5} T$ . The work done in rotating it through $180^{0}$ is

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Answer:

Solution:

$W = - M . B (\cos θ_{f} - \cos θ_{i})$

$= (-) 4 \times 5 \times 10^{- 5} (\cos 180 - \cos 0)$

$= - 20 \times 10^{- 5} (- 1 - 1)$

$= 4 \times 10^{- 4} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Properties of magnet

⏱ 2mℹ️ Source: PYQ_2020

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