The magnetic susceptibility of a material of a rod is 499 . Permeability of vacuum is 4 π × 10 - 7 H m - 1 . Absolute permeability of the material of the rod in H m - 1 is

We know μ = μ 0 1 + X ⇒ μ = 500 × 4 π × 10 - 7 ⇒ μ = 2 π × 10 - 4 H m - 1

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic properties of matterEasy2 minPYQ_2020

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The magnetic susceptibility of a material of a rod is $499$ . Permeability of vacuum is $4 π \times 10^{- 7} H m^{- 1}$ . Absolute permeability of the material of the rod in $H m^{- 1}$ is

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Answer:

Solution:

We know

$μ = μ_{0} (1 + X)$

$\Rightarrow μ = 500 \times 4 π \times 10^{- 7}$

$\Rightarrow μ = 2 π \times 10^{- 4} H m^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic properties of matter

⏱ 2mℹ️ Source: PYQ_2020

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