A paramagnetic substance, in the form of a cube with sides 1 cm , has a magnetic dipole moment of 20 × 10 - 6 J T - 1 , when a magnetic intensity of 60 × 10 3 A m - 1 is applied. Its magnetic susceptibility is

M = Magnetic moment per unit volume = 20 × 10 - 6 1 × 10 - 2 3 J T - 1 m - 3 = 20 J T - 1 m - 3 H = 60 × 10 3 A m - 1 χ = M H = 20 60 × 10 3 = 3.3 × 10 - 4

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PhysicsMagnetismMagnetic properties of matterEasy2 minPYQ_2020

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A paramagnetic substance, in the form of a cube with sides $1 cm$ , has a magnetic dipole moment of $20 \times 10^{- 6} J T^{- 1}$ , when a magnetic intensity of $60 \times 10^{3} A m^{- 1}$ is applied. Its magnetic susceptibility is

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Solution:

$M =$ Magnetic moment per unit volume $= \frac{20 \times 10^{- 6}}{{(1 \times 10^{- 2})}^{3}} J T^{- 1} m^{- 3}$

$= 20 J T^{- 1} m^{- 3}$

$H = 60 \times 10^{3} A m^{- 1}$

$χ = \frac{M}{H}$

$= \frac{20}{60 \times 10^{3}}$

$= 3.3 \times 10^{- 4}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic properties of matter

⏱ 2mℹ️ Source: PYQ_2020

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