Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A circular current carrying coil has a radius $R$ . The distance from the centre of the coil on the axis, where the magnetic induction will be $\frac{1}{8^{th}}$ to its value at the centre of the coil is

Options:

Answer:

Solution:

$\frac{B_{c e n t r e}}{B_{a x i s}} = {(1 + \frac{x^{2}}{R})}^{\frac{3}{2}}$

$B_{a x i s} = \frac{1}{8} B_{c e n t r e}$

$\frac{8}{1} = {(1 + \frac{x^{2}}{R^{2}})}^{\frac{3}{2}}$

$4 = 1 + \frac{x^{2}}{R^{2}}$

$3 = \frac{x^{2}}{R^{2}}$

$x^{2} = 3 R^{2}$

$x = \sqrt{3} R$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...