Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minPYQ_2020

PhysicsEasysingle choice

An electron of mass $m$ and electric charge $e$ is accelerated by a potential difference of $V$ and then it enters in a magnetic field $B$ perpendicular to the magnetic field lines. Radius of the circular path formed by electron is

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Answer:

Solution:

$Bev = \frac{{mv}^{2}}{r} or r = \frac{mv}{Be}$ as $mv = \sqrt{2 mT}$ $(T = KE)$ . So $r = \frac{\sqrt{2 mT}}{Be}$

As the electron has been accelerated from rest through a potential difference of $V$ volt, then $T = eV$

$∴ r = \sqrt{\frac{2 mVe}{B^{2} e^{2}}} = \sqrt{\frac{2 mV}{B^{2} e}}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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