If the vertical component of earth's magnetic field at a place is 3 times the horizontal component, then the value of dip at that place is

Here, B V = 3 B H We know that, angle of dip, θ = tan - 1 ⁡ B V B H ⇒ θ = tan - 1 ⁡ 3 B H B H = tan - 1 ⁡ 3 = 60 ° ∴ Angle of dip, θ = 60 °

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minPYQ_2020

PhysicsEasysingle choice

If the vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component, then the value of dip at that place is

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Answer:

Solution:

Here, $B_{V} = \sqrt{3} B_{H}$
We know that, angle of dip, $θ = \tan^{- 1} (\frac{B_{V}}{B_{H}})$

$\Rightarrow θ = \tan^{- 1} (\frac{\sqrt{3} B_{H}}{B_{H}}) = \tan^{- 1} (\sqrt{3}) = 60 °$

$∴$ Angle of dip, $θ = 60 °$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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