The work done in rotating a magnet of the magnetic moment 2 A m 2 in a magnetic field of induction 5 × 10 – 3 T from the direction along the magnetic field to the direction opposite to the field, is

W = M B ( 1 - c o s θ ) ; where θ = 18 0 ° ⇒ W = 2 M B ⇒ W = 2 × 2 × 5 × 1 0 - 3 = 2 × 10 - 2 J

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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentEasy2 minPYQ_2020

PhysicsEasysingle choice

The work done in rotating a magnet of the magnetic moment $2 A m^{2}$ in a magnetic field of induction $5 \times 10^{- 3} T$ from the direction along the magnetic field to the direction opposite to the field, is

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Solution:

$W = M B (1 - c o s θ);$ where $θ = 180 °$

$\Rightarrow W = 2 M B \Rightarrow W = 2 \times 2 \times 5 \times 1 0^{- 3} = 2 \times 10^{- 2} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2020

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