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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic torque & energyEasy2 minQB

PhysicsEasysingle choice

Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of $3 s$ and $4 s$ respectively. If their moments of inertia are in the ratio of $3 : 2$ then the ratio of their magnetic moments will be

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Solution:

Torque on a bar magnet kept in a magnetic field is given by $τ = M B \sin θ$ .
Hence, for small oscillations the time period of bar magnets is given by,
$T = 2 π \sqrt{\frac{I}{M B}} \Rightarrow M \propto \frac{I}{T^{2}}$
$\Rightarrow \frac{M_{1}}{M_{2}} = \frac{I_{1}}{I_{2}} \times {(\frac{T_{2}}{T_{1}})}^{2}$
$\Rightarrow \frac{M_{1}}{M_{2}} = \frac{3}{2} \times {(\frac{4}{3})}^{2} = \frac{8}{3}$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy

⏱ 2mℹ️ Source: QB

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