Physics - Magnetism Question with Solution | TestHub

The direction of magnetic field is along the direction of motion of the charge particles, so angle will be$0°.$

$\therefore \mathrm{F}\mathrm{o}\mathrm{r}\mathrm{c}\mathrm{e}\mathrm{ }F=qvB\sin \mathrm{\theta }$

$=qvB\sin \mathrm{\theta }$

$=0 (\because \sin \mathrm{\theta }=0)$

So, there will be no change in the velocity.