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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2020

PhysicsEasysingle choice

A long wire bent as shown in the figure carries current $I = 10 A$ . If the radius of the semicircular portion is $1 m$ , the magnetic induction (in $μT$ ) at the centre $C$ is

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Answer:

Solution:

B₁ (due to two semi-infinite straight wires) $= \frac{μ_{0}}{2 π} (\frac{I}{a}) \hat{k} = 2 \hat{k} μT$

B₂ (semi-circular loop) $= \frac{μ_{0} I}{4 a} (- \hat{i}) = - π \hat{i} μT$

$|\vec{B}| = \sqrt{B_{1}^{2} + B_{2}^{2}}$

$|\vec{B}| = \sqrt{π^{2} + 4} μT$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2020

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