Physics - Magnetism Question with Solution | TestHub

The applied magnetic field provides the required centripetal force to the charge particle, so it can move in circular path of radius $\frac{\mathrm{d}}{2}$ $$\therefore Bqv=\frac{m^2}{d/2}$$ or, $B=\frac{2\mathrm{mv}}{\mathrm{qd}}$ Time interval for which a uniform magnetic field is applied $$\Delta \mathrm{t}=\frac{\pi \cdot \frac{\mathrm{d}}{2}}{\mathrm{v}}$$ (particle reverses its direction after time $\Delta \mathrm{t}$ by covering semi circle). $$\Delta \mathrm{t}=\frac{\pi \mathrm{d}}{2\mathrm{v}}$$