As shown in the figure, two infinitely long, identical wires are bent by 90 o and placed in such a way that the segments L P and Q M are along the x - axis, while segments P S and Q N are parallel to

Question

As shown in the figure, two infinitely long, identical wires are bent by $90^{o}$ and placed in such a way that the segments $L P$ and $Q M$ are along the $x$ - axis, while segments $P S$ and $Q N$ are parallel to the $y$ - axis. If $O P = O Q = 4 c m,$ and the magnitude of the magnetic field at $O$ is $10^{- 4} T,$ and the two wires carry equal currents (see figure), the magnitude of the current in each wire and the direction of the magnetic field at $O$ will be $(μ_{0} = 4 π \times 10^{- 7} N A^{- 2}) :$

TestHub · Accepted Answer

As we know that the magnetic field due to a infinite wire at a distance of d is given as

$B = (\frac{μ_{0} i}{4 π d})$

but there are two wires so that the net magnetic field is given as

$B = 2 (\frac{μ_{0} i}{4 π d})$

$10^{- 4} = 2 \frac{4 π \times 10^{- 7} \times i}{4 π \times (\frac{4}{100})}$

$i = 20 A$

Physics - Magnetism Question with Solution | TestHub

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