Home
PYQ PracticeFree
JEE Rank Predictor
Answer Key

Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2019

PhysicsEasysingle choice

Find the magnetic field at point $P$ due to a straight line segment $A B$ of length $6 c m$ carrying a current of $5 A .$ (See figure) $(μ_{0} = 4 π \times 10^{- 7} {NA}^{- 2})$

Question diagram: Find the magnetic field at point P due to a straight line se

Options:

Answer:

A

Solution:

12.04.2019 Shift 2 Synergy JEE Mains D43

$θ = 37^{0}$
$r = 4 c m$
$B = \frac{μ_{0} i}{4 π r} [s i n 37 ° + s i n 37 °]$
$= \frac{4 π \times 10^{- 7} (5)}{4 π \times (4 \times 10^{- 2})} (\frac{3}{5} + \frac{3}{5})$
$= \frac{3}{2} \times 10^{- 5} = 1.5 \times 10^{- 5} T$

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2019

Doubts & Discussion

Loading discussions...